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Thermo Example 1†††††††††††††††††††††††††††††††††††††††††††††††††††††††††††††††††††††††††††††††††††† © 2000 D.P. Maloney

 

 

One hundred and fifty joules of heat are added to 75 g of a material whose specific heat is 1.25 J/g Co.If the materialís initial temperature was 43oC, what is its final temperature?

 

Given:††††††††††††

 

 

Unknown:††††††

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 


Physical Principles and/or Ideas:††† Temperature change of a material when heated, definition of specific heat.

 

Solution:†††††† This problem is reasonably straightforward.A material is being heated without undergoing any change of state.In such a situation, all of the heat added to the material goes into increasing the temperature of the material.The rate at which the temperature increases and the actual temperature change are determined by the mass of the material and the materialís specific heat.Using this relation, we find:

 

†††††††††††††††††††††††††††††††††††

So,

†††††††††††


Other Thermo Examples:    1     2     3     4     5
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